+
+
+{% markdown %}
+### String Split and Join
+
+This challenge involves a string containing spaces, where the spaces are to be
+replaced with dashes (`-`) instead.
+{% endmarkdown %}
+
+
+
+
+
+
+{% highlight python3 tio=https://tio.run/##K6gsycjPM/7/PyU1TaG4ICezJD4xLyU@Kz8zTyMnMy9V04pLAQiKUktKi/IUlHSV9OBSemDlGkoKSpqa/wuKMvNKNNAMyMwrKC3R0ARKp@XnKyQlFgFxFQA %}
+def split_and_join(line):
+ return "-".join(line.split(" "))
+{% endhighlight %}
+
+
+
+
+
+
+
+{% highlight perl6 tio=https://tio.run/##K0gtyjH7/7@4NEmhuCAns0Q3MS9FNys/M09BQyUnMy9VU6GaSwEIwBw9sBINJQUlTT2QGg0lXSVNrtr/KlqefnrFOaVFBXpqqKboFSdW/k/Lz1dISiwC4ioA %}
+sub split-and-join ($line) {
+ $line.split(" ").join("-")
+}
+{% endhighlight %}
+
+
+
+
+
+
+
+{% markdown %}
+### What's Your Name?
+
+The next challenge is a simply string formatting task. You get two inputs, a
+first name and a last name, and have to put it in a string which will be
+printed to `STDOUT`.
+{% endmarkdown %}
+
+
+
+
+
+
+{% highlight python3 tio=https://tio.run/##XYzBCsIwEETv/YqxUEigePHmD@jZm6cSyRYj22ww2UK/PobqyWEOAzPz0laeEk@1epqR3iGWaVbmKbqFjBvxsOcOTXtl@isxC4bcfMBdFC/NBZ54JY@2EKQdeOwx4Pu39R8bYtJi7IhfsPWiwUu3uoib5KzLBw %}
+def print_full_name(a, b):
+ print("Hello %s %s! You just delved into python." % (a, b))
+{% endhighlight %}
+
+
+
+
+
+
+
+{% highlight perl6 tio=https://tio.run/##K0gtyjH7/7@4NEmhoCgzr0Q3rTQnRzcvMTdVQyVRR0ElSVOhmksBCIoTKxWUPFJzcvIVVBKB4ooKkfmlClmlxSUKKak5ZakpCkDd@QoBQPMUzPSUuGr/Y5in5emnl55aAjQVytL875NYVFTJFZ6YkwMA %}
+sub print-full-name($a, $b) {
+ say "Hello $a $b! You just delved into Perl 6."
+}
+{% endhighlight %}
+
+
+
+
+
+
+
+{% markdown %}
+### Mutations
+
+You are given a string _string_, an integer _position_ and a character
+_character_. In _string_, replace the character at _position_ to the given
+_character_. The position is counted from starting point 0, so I don't have to
+think about differences between what a human or computer considers to be
+position 1 in a string.
+{% endmarkdown %}
+
+
+
+
+
+
+{% highlight python3 tio=https://tio.run/##VY5BC8IwDIXv/RVhpxaKIN4Ef4mIjNm5iCYlTQ/79bXrpmIuyeN975E468R0KOUWRnhl7TVckwrS3a7LQ@SEikwehqmXftAg7migzqITnOCJSTfc/YzzJ3ipyDdqGiBBsxB03e7BSLbxrsTaoPb/C6SY1ToPi7WJptbLlZHZ7I28AQ %}
+def mutate_string(string, position, character):
+ chars = list(string)
+ chars[position] = character
+
+ return "".join(chars)
+{% endhighlight %}
+
+
+
+
+
+
+
+{% highlight perl6 tio=https://tio.run/##K0gtyjH7/7@4NEkht7QksSRVt7ikKDMvXUFDBcLQUVApyC/OLMnMzwMykzMSixKTS1KLNBWquRSAILdSwSEns7hEwVYBqkEvOT83yRosCZaJhuuPBSmCm2DNhVCjl5WfmWfNVfsfxQ0aKlqefnrpqSVAizFYmnrFiZX/0/LzuQy5igA %}
+sub mutate-string ($string, $position, $character) {
+ my @list = $string.comb;
+ @list[$position] = $character;
+
+ @list.join;
+}
+{% endhighlight %}
+
+
+
+
+
+
+
+{% markdown %}
+### Find a String
+
+In the following challenge you are given a string _string_, and a substring
+_sub\_string_. The challenge is to find how often a substring occurs in the
+_string_. The substrings may overlap one another, so the string `"ABCDCDC"`
+contains the substring `"CDC"` twice.
+{% endmarkdown %}
+
+
+
+
+
+
+{% highlight python3 tio=https://tio.run/##XU67CsMwDNz9FTfaxENKt4CHPv4ilNCHkwqKbBx76Ne7bhxIqYSQdNzp5N/x6Xif88OOuLvEcZjTbY6BeJK1aRRkqLPqBEosRBi0YllHF0AgRrjyZGWr8bK8qtUq@QaNqGBPHaGprO32Bcb8eG26zbIx2FXPYGMKXOHsCz/K//eJfYpSaayDUvlwPJ1LilIf %}
+def count_substring(string, sub_string):
+ count = 0
+
+ for i in range(0, len(string)):
+ if string[i:i + len(sub_string)] == sub_string:
+ count += 1
+
+ return count
+{% endhighlight %}
+
+
+
+
+
+
+
+{% highlight perl6 tio=https://tio.run/##K0gtyjH7/7@4NEkhOb80r0QXyCouKcrMS1fQUIEwdBRUgIK6EI6mQjWXAhDkViqogDUo2CoYWHOBxdLyixTioJr0kjMSi4qhikEAolpbWyEzTQGmBmKXhko8ihUQrZoKqYXIotZgk2ohNkEMs@aq/Y/maA0VLU8/vfTUEqCJUJamXnFi5X9HJ2cXIOQCYgA %}
+sub count-substring ($string, $sub-string) {
+ my $count = 0;
+
+ for ^$string.chars {
+ $count++ if $string.substr($_, $sub-string.chars) eq $sub-string;
+ }
+
+ $count;
+}
+{% endhighlight %}
+
+
+
+
+
+
+
+{% markdown %}
+### String Validators
+
+In the following challenge, the program is given a string _s_, and have to
+validate a number of properties on this string. These are, in order, whether
+they contain
+
+- alphanumeric characters (a-z, A-Z or 0-9),
+- alphabetic characters (a-z or A-Z),
+- digits (0-9),
+- lowercase characters (a-z),
+- uppercase characters (A-Z).
+
+If any character in the given string passes a validation, it must print
+`"True"`, otherwise it must print `"False"`.
+
+{% endmarkdown %}
+
+
+
+
+
+
+{% highlight python3 tio=https://tio.run/##hZLNioMwEIDvPsXQPdTAIrS9CR72sk@wt1JCVtMaqklIIqWUPrubn6p1MZib38x8zmQi76YW/ND37AwYc9JSjKEoYItxSxjHeJsnYI@GAhiXnUlR4kFZ0/Lq6MN/urMhDe/aTQ7fpNH0853Lmizwil2YWeCNuFG1wDspJ@7xMzRzFso2RJRtERqmTapRPpbZybgwr4aPryZPQHjlazKmPUrfSqYBp/wCflRHk7jWzfhPa1FcG/JXtOGKZlqPYtohf0Ubbnim9SimHfJXtGFBM61HMe2QH7QQvFd6d@/K7zEkZg6lCI3hTAs1vkS3fAvd7l1s@pNUjA@Kow2dUN9//ZbVbn/4@AM %}
+if __name__ == '__main__':
+ s = input()
+
+ checks = {
+ "alnum": False,
+ "alpha": False,
+ "digit": False,
+ "lower": False,
+ "upper": False
+ }
+
+ for char in list(s):
+ if not checks["alnum"] and char.isalnum():
+ checks["alnum"] = True
+
+ if not checks["alpha"] and char.isalpha():
+ checks["alpha"] = True
+
+ if not checks["digit"] and char.isdigit():
+ checks["digit"] = True
+
+ if not checks["lower"] and char.islower():
+ checks["lower"] = True
+
+ if not checks["upper"] and char.isupper():
+ checks["upper"] = True
+
+ keys = list(checks.keys())
+ keys.sort()
+
+ for key in keys:
+ print(checks[key])
+{% endhighlight %}
+
+
+
+
+
+
+
+{% highlight perl6
+tio=https://tio.run/##K0gtyjH7/7@4NEnB19HTT6GaSwEIcisVVIoVbBVUtDz99NJTS6y5wMLFiZUKxfkgqbo6BX2bxJy80lw7fWvscgUZiTjkUjLTM0twyOXkl6cW4ZArLSiAyNX@/@@YlJxiaGSsDAA %}
+sub MAIN {
+ my $s = $*IN.get;
+
+ say so $s ~~ /
/;
+ say so $s ~~ //;
+ say so $s ~~ //;
+ say so $s ~~ //;
+ say so $s ~~ //;
+}
+{% endhighlight %}
+
+
+
+
+
+
+
+{% markdown %}
+### Text Wrap
+
+You are given a string _s_ and a width _w_. The string should be split over
+multiple lines so it is never more wide than _w_.
+{% endmarkdown %}
+
+
+
+
+
+
+{% highlight python3 tio=https://tio.run/##K6gsycjPM/7/PzO3IL@oRKEktaKkvCixgIsrJTVNAcTSKC4pysxL11HITayIL89MKcnQtOJSAIKi1JLSojwFpZg8Jb2s/Mw8DZhePRzaNP8XAIVKNMDSmXkFpSUamjoKIBEoBwj@Ozo5u7i6uXt4enn7@Pr5BwQGBYeEhoVHREZxmQIA %}
+import textwrap
+
+def wrap(string, max_width):
+ return "\n".join(textwrap.wrap(string, max_width))
+{% endhighlight %}
+
+
+
+
+
+
+
+{% highlight perl6 tio=https://tio.run/##K0gtyjH7/7@4NEmhvCixQEFDpbikKDMvXUdBpTwzpSRDU6GaSwEIoMJ6yfm5SRpQKb2s/Mw8DaWYPCVNrtr/IO0aKlqefnrpqSVA7VCWnmdeiaZecWLlf0cnZxdXN3cPTy9vH18//4DAoOCQ0LDwiMgoLlMA %}
+sub wrap ($string, $width) {
+ $string.comb($width).join("\n")
+}
+{% endhighlight %}
+
+
+
+
+
+
+
+{% markdown %}
+### Designer Door Mat
+
+This challenge is more complex than previous challenges. The task at hand is to
+"draw" a certain "design" as the output. For the input, you are given both a
+height _y_ and a width _x_, however _x_ must always be _y_ × 3, so you can
+ignore the second argument.
+
+This one is much simpler to explain using two examples. The first example is
+the output if the input were `7 21`.
+{% endmarkdown %}
+
+{% highlight text %}
+---------.|.---------
+------.|..|..|.------
+---.|..|..|..|..|.---
+-------WELCOME-------
+---.|..|..|..|..|.---
+------.|..|..|.------
+---------.|.---------
+{% endhighlight %}
+
+{% markdown %}
+In the second example, the input is `11 33`.
+{% endmarkdown %}
+
+{% highlight text %}
+---------------.|.---------------
+------------.|..|..|.------------
+---------.|..|..|..|..|.---------
+------.|..|..|..|..|..|..|.------
+---.|..|..|..|..|..|..|..|..|.---
+-------------WELCOME-------------
+---.|..|..|..|..|..|..|..|..|.---
+------.|..|..|..|..|..|..|.------
+---------.|..|..|..|..|.---------
+------------.|..|..|.------------
+---------------.|.---------------
+{% endhighlight %}
+
+
+
+
+
+
+{% highlight python3 tio=https://tio.run/##zZDNS8MwGMbv@SseMwbJlrbrehCEnWS3DS@CBxGpNFsCJQ1p5xD832s@Nh2I7GpyCHmf3/u8H/ZjUJ2pxnFyg@LQu@JNm0Kad9gkEKKk3qsBK2gzMKaNPQyM571ttX/58@KFk6NuBuWJEzpDRVTd7s45p3CGkqPAkhMywWNnERiy6xxabaRH4Wqzl6wUUcHc83cE/pjOvDZ1r2TvLRmL@MwbRctIfKuxYOonA7tI9E3xc/mQYV1A6bQPl2IKRjPqqYQL0PwzD/8fCx@7IHgcY6ubppVxAPLbMRZKSSxoqa8idV5xkfSn9eb@Ybum4gpOUslNd5Tur92FsMBCIPvfuxvHWyzLLw %}
+#! /usr/bin/env python3
+
+height = int((input().split())[0])
+width = height * 3
+half = int((height - 1) / 2)
+
+# Top half
+for line in range(1, half + 1):
+ non_dashes = ((line * 2) - 1)
+ dashes = int((width - (non_dashes * 3)) / 2)
+
+ print("%s%s%s" % ("-" * dashes, ".|." * non_dashes, "-" * dashes))
+
+# Middle line
+print("%s%s%s" % (
+ "-" * (int(width / 2) - 3),
+ "WELCOME",
+ "-" * (int(width / 2) - 3)
+))
+
+# Lower half
+for line in range(half, 0, -1):
+ non_dashes = ((line * 2) - 1)
+ dashes = int((width - (non_dashes * 3)) / 2)
+
+ print("%s%s%s" % ("-" * dashes, ".|." * non_dashes, "-" * dashes))
+{% endhighlight %}
+
+
+
+
+
+
+
+{% highlight perl6 tio=https://tio.run/##zZBBTsMwEEX3PsXgdpEgxVFSqSwiVqiLSi1skFiiIE@xpeBEdtpQhZyDo3CAHix0UpKGSuzxypp5/8/XL9Bm87adXEG4dTZ80SZEs4OCxoy97WGqUL@qEm5her28Fy7b2kJUuZVOKEylWJoy6bhKy1IR9iM4fMLstFFptgkGG68HAoh8OHxBnDA2gce8AALZJrcQCfFLVTM4PvIyuQlk6hS6zuqZzsQ@eSUDM9qfQgXH30hIyfzhNKlcugde84DDey9vai4@RDc4S5sLhiesofBrLWWGkGmDbOzl9QnoFqWc@c3TYnX3sF7U8DfCu0ZWeYX23Il3UYovLO7QOvzX7bTtDcTRNw %}
+#! /usr/bin/env perl6
+
+my $height = $*IN.slurp.words.head.Int;
+my $width = $height × 3;
+my $half-height = ($height - 1) ÷ 2;
+
+# Top half
+for 1..$half-height {
+ my $non-dashes = ($_ × 2) - 1;
+ my $dashes = ($width - ($non-dashes × 3)) ÷ 2;
+
+ say "{"-" x $dashes}{".|." x $non-dashes}{"-" x $dashes}";
+}
+
+# Middle line
+say "{"-" x (($width ÷ 2) - 3)}WELCOME{ "-" x (($width ÷ 2) - 3)}";
+
+# Lower half
+for (1..$half-height).reverse {
+ my $non-dashes = ($_ × 2) - 1;
+ my $dashes = ($width - ($non-dashes × 3)) ÷ 2;
+
+ say "{"-" x $dashes}{".|." x $non-dashes}{"-" x $dashes}";
+}
+{% endhighlight %}
+
+
+
+
+
+
+
+{% markdown %}
+### String Formatting
+
+In this challenge, you are to produce a table with four columns. The columns
+should contain the decimal, octal, hexadecimal and binary values of the row
+numbers. The function receives an int _number_. The table should contain that
+many rows, starting with row number 1.
+{% endmarkdown %}
+
+
+
+
+
+
+{% highlight python3 tio=https://tio.run/##jZFNCoMwEIX3nmIQhIQG0XYn9CwSTawpJoYYqVJ6dht/W7uQDlll3vveTKJ7W9bqMgyMF6CNUDYtaiOptZwh1cqMG5x44ErSLn0IZku4QsUV8p9Rkr38cJavWuxNYncJAoQCQ9WNo5jA3IcTxAtvLMZzIWnliI72YQkcmnvbWLRl4s1S53Y1JPV/lpJ3dJeUdDtjqzU36ACQCUVNv3iz49DNND0m8oMG1uNDAGgZhMyLkO/hyBKE8fD7EyNKKN1ahF33HL0B %}
+def print_formatted(number):
+ max_width = len("{0:b}".format(number))
+
+ for i in range(1, number + 1):
+ decimal = "{0}".format(i).rjust(max_width)
+ octal = "{0:o}".format(i).rjust(max_width)
+ hexadecimal = "{0:x}".format(i).upper().rjust(max_width)
+ binary = "{0:b}".format(i).rjust(max_width)
+
+ print("%s %s %s %s" % (decimal, octal, hexadecimal, binary))
+{% endhighlight %}
+
+
+
+
+
+
+
+{% highlight perl6 tio=https://tio.run/##XY9NCsIwEIX3PcUQIiRiB1tEBPEA3bhxK0iq0VZMWpIUK1KvXmNb/HurGWbeN29KaS7ztrVVCqXJtQuPhVHCOXkARnWlUmk43APwUjegStThNT@4DFYwjDEVVrKY48YZ3GfC2OV7vYeF1nn0yVsYGd0/jMYSqGuYcTwXuWYECIcHkK0my6BDeDtEiMOhIcZLv2Dskh8Z3U2A7vo8C/6po/lXE3Pe52uCpv17mdFxssaTdJhox9t4@gQ %}
+sub print-formatted ($number) {
+ my $max-width = $number.base(2).Str.chars;
+ my $format-string = ("%{$max-width}s" xx 4).join(" ") ~ "\n";
+
+ for 1..$number {
+ $format-string.printf($_, $_.base(8), $_.base(16), $_.base(2));
+ }
+}
+{% endhighlight %}
+
+
+
+
+
+
+
+{% markdown %}
+## Wrap-up
+
+This time I did not do all of the challenges, as the post would probably get
+too long. I still did 8 of them, and might do the rest of the string challenges
+in a later part anyway.
+
+I still find Perl 6 to produce much cleaner code, which is shown best with the
+first challenge. In Perl 6 (`$line.split(" ").join("-")`), I can read from left
+to right to see what I'm doing: I have a `$line`, which I split, and then join.
+In the Python variant (`"-".join(line.split(" "))`), it is much less clear what
+the actual item I'm working on is, as it's hidden inbetween the `join` and
+`split` calls.
+
+Of course, I'm still not an expert on Python 3 code, so I'm sure that there are
+many parts that could be written in a cleaner fashion. I'm still open for
+feedback to improve my Python 3 skills (hence I'm publishing these posts), so
+please let me know if you know better ways to solve some challenges.
+{% endmarkdown %}
--
cgit v1.1